a) Mean of the sample considering the outlier:
[tex]\mu=\frac{\Sigma x_i}{n}[/tex]
n=10.
Therefore:
[tex]\mu=\frac{-8-7+3+7+8-1-1-1-3+83}{10}=8[/tex]
b) Removing the outlier:
Outlier= 83.
The mean will be:
[tex]\mu=\frac{-8-7+3+7+8-1-1-1-3}{9}=-\frac{1}{3}=-0.33[/tex]
Answer:
a) Mean with the outlier: 8
b) Mean removing the outlier: -0.33
