Respuesta :

a) Mean of the sample considering the outlier:

[tex]\mu=\frac{\Sigma x_i}{n}[/tex]

n=10.

Therefore:

[tex]\mu=\frac{-8-7+3+7+8-1-1-1-3+83}{10}=8[/tex]

b) Removing the outlier:

Outlier= 83.

The mean will be:

[tex]\mu=\frac{-8-7+3+7+8-1-1-1-3}{9}=-\frac{1}{3}=-0.33[/tex]

Answer:

a) Mean with the outlier: 8

b) Mean removing the outlier: -0.33

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