How many moles of iron (III) hydroxide are produced when 5.0 moles of sodium hydroxide reacts with excess iron (III) chloride?

So,
We want to find the number of moles of Fe(OH)3 produced from 5.0 moles of NaOH according to the reaction:
We can see that NaOH and Fe(OH)3 have a 3:1 ratio due to the reaction coefficients. This means that, per each mol of Fe(OH)3, 3 moles of NaOH react.
Using this proportion, we have:
Therefore, the answer is 1.7 moles of Fe(OH)3.