[tex]\begin{gathered} \text{The quadratic equation is,} \\ 2x^2-8x+9=0 \\ So,\text{ }apply\text{ the quadratic formula} \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Here, a=2,b=-8,c=9} \\ So, \\ x=\frac{8\pm\sqrt[]{(-8)^2-4\times2\times9}}{2\times2} \\ x=\frac{8\pm\sqrt[]{64-72}}{4} \\ x=\frac{8\pm\sqrt[]{-8}}{4} \\ x=2\pm\frac{i}{2} \end{gathered}[/tex]