Question

Sodium bicarbonate decomposes when heated to form sodium carbonate, carbon dioxide, and water. The equation is: 2NaHCO3 (s) + 85 kJ --> Na2CO3 (s) + H2O (I) + CO2 (g) How much heat would be required to decompose 100.0 grams of NaHCO3? Answers: 170 kJ 4,250 kJ 50.6 kJ 101 kJ

Answer 1

Answer

50.6 kJ

Explanation

According to the given equation:

2NaHCO3 (s) + 85 kJ --> Na2CO3 (s) + H2O (I) + CO2 (g)

85 kJ of heat decomposed 2 moles of NaHCO3

1 mole of NaHCO3 = 84.007 g/mol

2 moles of NaHCO3 = (2 x 84.007) = 168.014 grams

So if 168.014 grams NaHCO3 required 85 kJ

100.0 grams NaHCO3 will require

$\frac{100.0\text{ }g}{168.014\text{ }g}\times85\text{ }kJ=50.60\text{ }kJ$

Therefore, the heat required to decompose 100.0 grams of NaHCO3 is 50.6 kJ