Answer:
[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]Explanation:
We can see that 20 is equal to 80 divided by 4 and 5 is equal to 20 divided by 4. Additionally, the sign change for every term. So, the explicit formula for an is:
[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]So, we can prove that this equation applies for the first 3 terms as:
[tex]\begin{gathered} a_1=80\cdot(\frac{-1}{4})^{1-1}=80 \\ a_2=80\cdot(\frac{-1}{4})^{2-1}=-20 \\ a_3=80\cdot(\frac{-1}{4})^{3-1}=5 \end{gathered}[/tex]Therefore, the answer is:
[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]