Respuesta :

Answer:

[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]

Explanation:

We can see that 20 is equal to 80 divided by 4 and 5 is equal to 20 divided by 4. Additionally, the sign change for every term. So, the explicit formula for an is:

[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]

So, we can prove that this equation applies for the first 3 terms as:

[tex]\begin{gathered} a_1=80\cdot(\frac{-1}{4})^{1-1}=80 \\ a_2=80\cdot(\frac{-1}{4})^{2-1}=-20 \\ a_3=80\cdot(\frac{-1}{4})^{3-1}=5 \end{gathered}[/tex]

Therefore, the answer is:

[tex]a_n=80\cdot(\frac{-1}{4})^{n-1}[/tex]

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