Question

(-2, 7) and (6, -5)Linear equation HELP PLEASE:)

Answer 1

First we need to calculate the slople

P1=(-2,7)=(x1,y1)

P2=(6,-5)=(x2,y2)

$m=\frac{y2-y1}{x2-x1}$$m=\frac{-5-7}{6+2}=\frac{12}{8}=\frac{3}{2}$

Then we can calculate the linear equation

$(y-y_1)=m(x-x_1)$$(y-7)=\frac{3}{2}(x+2)$$(y-7)=\frac{3}{2}x+3$$y=\frac{3}{2}x+3+7$$y=\frac{3}{2}x+10$

the linear equation is y=3/2 x+10