Respuesta :

For the first table

Let's pick 2 points

x₁ = 0 y₁= 17

x₂ = 3 y₂ = 11

To form the equation, we will use the formula;

[tex]y-y_1=\text{ }\frac{y_2-y_1}{x_2-x_1}=(x-x_1)[/tex]

substitute the values into the formula;

[tex]y-17=\frac{11-17}{3-0}(x-0)[/tex]

Evaluate

[tex]y-\text{ 17 =}\frac{-6}{3}(x-0)[/tex]

y - 17 = -2x

add 17 to both-side of the equation

y= -2x + 17

The above is the equation of the line for the first table

Fo the second table

Let's also pick 2 points

x₁ = 3 y₁= -2

x₂ = 6 y₂ = -4

Substitute into the formula;

[tex]y\text{ - (-2) =}\frac{-4+2}{6-3}(x-3)[/tex]

Evaluate

[tex]y\text{ + 2 =}\frac{-2}{3}(x\text{ - 3)}[/tex][tex]y\text{ + 2=-}\frac{2}{3}x\text{ + 2}[/tex]

subtract 2 from both-side of the equation

[tex]y=-\frac{2}{3}x[/tex]

The above is the equation for table 2

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