Question

Three forces, described by 1-3 newtons, - 5 newtons), (-8 newtons , 6 newtons).and (6 newtons, 3 newtons), are acting on an object. What is the magnitudeof the net force acting on the object? Round your answer to the nearest tenth of a newton.

Answer 1

STEP 1

Find the net force by finding the sum of the individual forces for their respective x and y components

When we sum the above, we have the net force as:

$\begin{gathered} \text{Net force =(-3+(-8)+6),(-5)+6}+3) \\ \text{Net force=(-5 newtons and 4 newtons)} \end{gathered}$

STEP 2:

We find the magnitude of the net force by using the formula below:

$\begin{gathered} M\text{agnitude of net force = }\sqrt[]{x^2+y^2} \\ =\text{ }\sqrt[]{(-5)^2+4^2} \\ =\sqrt[]{25+16} \\ =\sqrt[]{41} \\ =6.4\text{ newtons} \end{gathered}$

In conclusion, the magnitude of the net force is 6.4 newtons