A scientist observes light from a star with a wavelength 2 of 97 nanometers (9.7 x 10% mì What is the photon energy. E of this lightUse this information to help youvaispeed of light in a vacuum, c=3.00 x 10 meters/second• Planck's constant, h=4.136 x 10-15 ev s

Respuesta :

Given data

The wavelength of the starlight is lambda 2 = 97 nanometers

The expression for the photon energy is given as:

[tex]E=\frac{hc}{\lambda_2}[/tex]

Substitute the value in the above equation.

[tex]\begin{gathered} E=\frac{4.136\times10^{-15}\text{ eVs }\times3\times10^8\text{ m/s}}{97\text{ nm}}\times\frac{1\text{ nm}}{10^{-9}\text{ m}} \\ E=12.79\text{ eV} \end{gathered}[/tex]

Thus, the photon energy is 12.79 eV.

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