Answer:
The product of -3-i and 3+3i is;
[tex]-6-12i[/tex]Explanation:
We want to multiply the complex number;
[tex]\begin{gathered} (-3-1)\times(3+3i) \\ (-3-i)(3+3i) \\ -3(3)-3(3i)-i(3)-i(3i) \\ -9-9i-3i-3i^2 \\ -9-12i-3(-1) \\ -9-12i+3 \\ -9+3-12i \\ -6-12i \end{gathered}[/tex]Therefore, the product of -3-i and 3+3i is;
[tex]-6-12i[/tex]