TRIGONOMETRY Find the horizontal and vertical components of this vector round to the nearest tenth

Let's take a closer look at our vector:
Now, notice that the angle a and the 130° angle given in the plot are a linear pair. This way,
[tex]\begin{gathered} a+130=180\rightarrow a=180-130 \\ \Rightarrow a=50 \end{gathered}[/tex]Therefore, our graph would be:
Since this is a right triangle, we'll have that:
[tex]\cos 50=\frac{Wx_{}}{W}\rightarrow Wx=W\cos 50[/tex]And that:
[tex]\sin 50=\frac{Wy}{W}\rightarrow Wy=W\sin 50[/tex]Notice that the horizontal component is going to the left (negative) and that the vertical component is going down (negative). This way, we'll have that:
[tex]\begin{gathered} Wx=-W\cos 50 \\ Wy=-W\sin 50 \end{gathered}[/tex]Plugging in the magnitude of the vector (19),
[tex]\begin{gathered} Wx=-19\cos 50\rightarrow Wx=-12.2 \\ Wy=-19\sin 50\rightarrow Wy=-14.6 \end{gathered}[/tex]This way, we can conclude that the horizontal component is -12.2 and that the vertical component is -14.6