Question

The length of a rectangle is 4 times the width.The perimeter of the rectangle is 45 inches. Write a system of equations

Answer 1

Explanation:

Let 'L' be the length, 'W' be the width.

The length is 4 times the width:

$L=4W$

The perimeter of a rectangle is the sum of the sides, which is twice the length plus twice the width:

$2L+2W=45$

Rewriting the first equation with both variables L and W on the same side:

$L-4W=0$

Answer:

The system of equations is:

$\begin{cases}L-4W=0 \\ 2L+2W=45\end{cases}$