gowerjennifer
gowerjennifer gowerjennifer
  • 17-02-2017
  • Chemistry
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Calculate the heat change in calories for condensation of 20.0 g of steam at 100∘C.

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scme1702
scme1702 scme1702
  • 24-02-2017
The latent heat of vaporization of steam is equal to its latent heat of condensation. The heat released is given by:
Q = ml
Q = 20 x 2257 joules/gram
Q = 45.14 kJ of heat is removed from the steam

1 calorie = 4.184 kJ
45.14 kJ = 10.8 cal of energy

The energy removed is 10.8 calories
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