The potential difference is 14.4 V.
Given data:
The length of wire is l=100 m.
The resistivity of the copper is ρ=1.70x10^-8 Ωm.
The diameter of wire is d=1.50 mm.
The current in the wire is I=15 A.
The resistance of the wire can be calculated as,
[tex]\begin{gathered} R=\rho\frac{L}{A} \\ R=\rho\frac{L}{\frac{\pi}{4}d^2} \\ R=(1.7\times10^{-8})\frac{100}{\frac{\pi}{4}(1.5\times10^{-3})^2} \\ R=0.962\text{ }\Omega \end{gathered}[/tex]The potential difference can be calculated using the Ohm's law,
[tex]\begin{gathered} \Delta V=IR \\ \Delta V=(15)(0.962) \\ \Delta V=14.4\text{ V} \end{gathered}[/tex]Thus, the potential difference is 14.4 V.
