Given a loan with principal amount, P, time, T, in years and rate, R %,
the interest I is given by
[tex]I=\frac{PRT}{100}[/tex]For the 4-year loan,
P = $10000, R = 4%, T = 4years
[tex]I=\frac{10000\times4\times4}{100}=\text{ \$1600}[/tex]For the 6-year loan,
P = $10000, R = 5%, T = 6years,
therefore,
[tex]I=\frac{10000\times5\times6}{100}=\text{ \$3000}[/tex]Hence,
the difference = $3000 - $1600 = $1400