i need to find the missing angle using trig ratios for this problem

we use the trigonometric ratio sine, so
[tex]\begin{gathered} \sin x=\frac{opposite}{hypotenuse} \\ \sin x=\frac{10}{39} \\ x=\sin ^{-1}(\frac{10}{39}) \\ x=14.86 \end{gathered}[/tex]answer:
angle = 14.86°