Lets solve this
[tex]\cos (\frac{\pi}{6})\text{ =}\frac{\sqrt[]{3}}{2}[/tex][tex]\sin (\frac{\pi}{6})=\frac{1}{2}[/tex][tex]\tan (\frac{\pi}{6})=\frac{1}{\sqrt[]{3}}[/tex][tex]\cos (\frac{\pi}{3})=\text{ }\frac{1}{2}[/tex][tex]\sin (\frac{\pi}{3})=\frac{\sqrt[]{3}}{2}[/tex][tex]\tan (\frac{\pi}{3})\text{ = }\sqrt[]{3}[/tex]