Question

I got -3x^8 but i think i solved it wrong... i just divided 3 the radical to the exponent 24 and got 8 and then found what was multiplied 3 times it self into -27 then I got 3 square toot (-3x^8)^3 and the radical 3 divided out 3 and left me with -3x^8 but that doesn't make any sense. Can I have step by step guide?

Answer 1

Given:

$\sqrt[3]{-27x^{24}}$

a)

Yes the expression is a perfect root because we can take a rrot as a real number.

b)

$\sqrt[3]{-27x^{24}}=\sqrt[3]{-3^3\times x^{^8}\times x^{^8}\times x^{^8}}$$\sqrt[3]{-27x^{24}}=-3x^8$

c)

Simplified form is negative because cube root of negative is negative.