Since the zeroes are 1/3 which has multiplicity 2, -4 and i, then
The factors of the polynomial are
[tex]x=\frac{1}{3}\rightarrow3x=1\rightarrow(3x-1)\rightarrow(3x-1)^2[/tex][tex]x=-4\rightarrow(x+4)[/tex][tex]x=i\rightarrow(x-i)(x+i)\rightarrow x^2-i^2\rightarrow(x^2+1)[/tex]Multiply the 3 factors
[tex]\begin{gathered} (3x-1)^2=(9x^2-6x+1) \\ U=(9x^2-6x+1)(x+4)(x^2+1) \end{gathered}[/tex]Multiply The first 2 brackets
[tex]U=(9x^3+36x^2-6x^2-24x+x+4)(x^2+1)[/tex]Add the like terms in the 1st bracket
[tex]U=(9x^3+30x^2-23x+4)(x^2+1)[/tex]Multiply the 2 brackets
[tex]U=9x^5+30x^4-23x^3+4x^2+9x^3+30x^2-23x+4[/tex]Add the like terms
[tex]U=9x^5+30x^4-14x^3+34x^2-23x+4[/tex]Since the leading coefficient is 63, multiply all terms by 7
[tex]U=63x^5+210x^4-98x^3+238x^2-161x+28[/tex]