Question

What is the area of a rectangle with side lengths of 6/8 meter and 4/10 meter? In fraction in simplest form

Answer 1

SOLUTION

We want to find the area of the rectangle with the given side lengths as indicated in the question.

The area of a rectangle is given as

$\text{Area = leghth }\times\text{ width}$

So, this means to get the area, we will multiply the side lengths, we have

$\begin{gathered} \text{Area = leghth }\times\text{ width} \\ \text{Area = }\frac{6}{8}\times\frac{4}{10} \end{gathered}$

Solving the fraction, we have

$\begin{gathered} \text{Area = }\frac{6}{8}\times\frac{4}{10} \\ 4\text{ divide itself is 1, }8\text{ divide 4 is 2, we have } \\ \text{Area = }\frac{6}{2}\times\frac{1}{10} \\ \text{now, 2 divide itself is 1, 6 divide 2 is 3, we have } \\ \text{Area = }\frac{3}{1}\times\frac{1}{10} \\ \text{Area = }\frac{3}{10} \end{gathered}$

Hence the area in fraction in the simplest form is

$\frac{3}{10}\text{ meter}$