We have
[tex]y=x^2-2x-5[/tex]where
a=1
b=-2
c=-5
First we need to find the vertex, with the next formula we will find the x-coordinate of the vertex.
[tex]x=\frac{-b}{2a}[/tex]we substitute the values
[tex]\begin{gathered} x=\frac{-(-2)}{2(1)} \\ x=\frac{2}{2} \\ x=1 \end{gathered}[/tex]then we substitute the value of the x-coordinate in the original equation in order to find the y-coordinate
[tex]\begin{gathered} y=1^{2}-2(1)-5 \\ y=1-2-5 \\ y=-6 \end{gathered}[/tex]the coordinates of the vertex is (1,-6)
the vertex form of the parabola is
[tex]y=a\mleft(x-h\mright)^2+k[/tex]where h is the x-coordinate of the vertex and k is the y-coordinate of the vertex, the vertex form of this parabola is
[tex]y=(x-1)^2-6[/tex]