Respuesta :

Given equation,

[tex]-4x+4y=16[/tex]

Now, put x = 0 in the given equation.

[tex]\begin{gathered} -4\times0+4y=16 \\ 4y=16 \\ y=4 \end{gathered}[/tex]

Thus, the point (x,y) will be (0,4).

Now, put x =3

[tex]\begin{gathered} -4\times3+4y=16 \\ -12+4y=16 \\ 4y=16+12 \\ 4y=28 \end{gathered}[/tex]

Now,

[tex]\begin{gathered} y=\frac{28}{4} \\ y=7 \end{gathered}[/tex]

Thus, the point (x,y) will be (3,7).

Now put y = 0

[tex]\begin{gathered} -4x+4y=16 \\ -4x+4\times0=16 \\ -4x=16 \\ x=-4 \end{gathered}[/tex]

Thus, the point (x,y) will be (-4,0).

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