We are given the area of the pool and the length.
We could easily obtain the breadth. Since;
[tex]\begin{gathered} A=l\times b \\ b=\frac{A}{l} \end{gathered}[/tex]Thus, the breadth is;
[tex]\begin{gathered} b=\frac{168}{14} \\ b=12ft \end{gathered}[/tex]We can now obtain the perimeter,
[tex]\begin{gathered} P=2(l+b) \\ P=2(14+12) \\ P=2(26) \\ P=52ft \end{gathered}[/tex]Therefore the perimeter of the pool is 52ft.