Respuesta :

Given:

[tex]f(x)=2\sin(3x)[/tex]

Required:

To find the period and amplitude of the given function.

Explanation:

Given function is in the form of

[tex]y=a\sin bx[/tex]

Here the amplitude is

[tex]=|a|[/tex]

Period

[tex]=\frac{2\pi}{b}[/tex]

Now consider the given function

[tex]y=2\sin3x[/tex]

Here the amplitude is

[tex]\begin{gathered} =|2| \\ =2 \end{gathered}[/tex]

And period is

[tex]=\frac{2\pi}{3}[/tex]

Final Answer:

The amplitude is 2 and the period is

[tex]\frac{2\pi}{3}[/tex]

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