Question

Find the equation of a circle with the center at ( 2, 3 ) and a radius of 6.

Answer 1

Explanation

We are asked to get the equation of the circle with the centre at (2,3) and a radius of 6

To do so, we will have to use the fact that the equation defines the equation of a circle

$\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ where \\ a,b=center \\ a=2,b=3 \\ r=6 \end{gathered}$

So, we will substitute the above into the formula

We will have the equation as

$(x-2)^2+(y-3)^2=6^2$