Answer:
(16.5, 7.5)
Explanation:
Given the two endpoints of a line segment AB:
[tex]A(x_1,y_1)\text{ and B}(x_2,y_2)[/tex]The midpoint of AB is derived using the formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Given the points T(16, 2) and U(17, 13), the midpoint of TU therefore, is:
[tex]\begin{gathered} (\frac{16+17}{2},\frac{2+13}{2}) \\ =(\frac{33}{2},\frac{15}{2}) \\ =(16.5,7.5) \end{gathered}[/tex]The midpoint of TU is (16.5, 7.5).
