Question

in a 45 45 90° triangle given the leg equals 8 find the hypotenuse of the triangle

Answer 1

11.31

Explanation

Step 1

use sin function

$\begin{gathered} \sin \vartheta=\frac{adjacent\text{ leg}}{\text{hypotenuse}} \\ \text{isolate hypotenuse} \\ \text{hypotenuse}=\frac{adjacent\text{ leg}}{\text{sin}\vartheta} \end{gathered}$

then, Let

angle=45

leg=8

hypotenuse=x

Now, replace

$\begin{gathered} \text{hypotenuse}=\frac{adjacent\text{ leg}}{\text{sin}\vartheta} \\ x=\frac{8}{\sin \text{ 45}} \\ x=11.31 \end{gathered}$

Hence the hypotenuse is 11.31