Question

A spinner has 3 sides labeled A, B, and C. The spinner is spun twice, what is the probability of at least landing on one A.

Answer 1

The probability of landing in A is:

$\frac{1}{3}$

Now, the probability of landing at least one time in A, for two spins is:

$\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$