Respuesta :
Answer:
a) Geometric Sequence
[tex]a_n=3\times2^{n-1}[/tex]b) Arithmetic Sequence
[tex]a_n=a_1+5(n-1)[/tex]Explanation:
a) We have the sequence: 3, 6, 12
For arithmetic sequences, the difference between successive terms are equal:
[tex]\begin{gathered} d=6-3=12-6 \\ d=3=6 \\ \therefore d=3\ne6 \end{gathered}[/tex]This is not an arithmetic sequence
For geometric sequences, the ratio of successive terms are found to be equal:
[tex]\begin{gathered} r=\frac{6}{3}=\frac{12}{6} \\ r=2=2 \\ \therefore r=2=2 \end{gathered}[/tex]This is a geometric sequence
Its formula is thus given as:
[tex]\begin{gathered} a_1=3 \\ r=\frac{12}{6}=2 \\ \text{The general equation of a geometric sequence is given by:} \\ a_n=a_1\cdot r^{n-1} \\ \text{Substituting the values of the known variables into the equation, we have:} \\ a_n=3\times2^{n-1} \\ \\ \therefore a_n=3\times2^{n-1} \end{gathered}[/tex]b) We have the sequence: 3, 8, 13
For arithmetic sequences, the difference between successive terms are equal:
[tex]\begin{gathered} d=8-3=13-8 \\ d=5=5 \\ \therefore d=5=5 \end{gathered}[/tex]This is an arithmetic sequence
Its formula is thus given as:
[tex]\begin{gathered} a_1=3 \\ d=8-3=5 \\ \text{The general formula for arithmetic sequence is given by:} \\ a_n=a_1+(n-1)d \\ \text{Substituting the values of the known variables into the equation, we have:} \\ a_n=3+5(n-1) \\ \\ \therefore a_n=3+5(n-1) \end{gathered}[/tex]