We have a normal distribution for our variable, with mean 2 and standard deviation of 0.5 minutes.
We have to calculate the probability that the variable takes a value of 3 or more.
If we calculate the z value, we get:
[tex]z=\frac{X-\mu}{\sigma}=\frac{3-2}{0.5}=\frac{1}{0.5}=2[/tex]Then, the probability we are looking for is:
[tex]P(X>3)=\Phi(z>2)[/tex]We can look for this probability in a standard normal distribution table or use an app, and its value will be 0.02275.