A person wants to increase a (5 in. x 7 in.) photo to an (8 in. x 10 in.) but since the aspect ratios are not the same some of the picture will get chopped off.

A person wants to increase a 5 in x 7 in photo to an 8 in x 10 in but since the aspect ratios are not the same some of the picture will get chopped off class=

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SOLUTION

Consider the image below

The image should have the leghth x

Hence by comparing the ratio of the side

[tex]\begin{gathered} \frac{x}{7}=\frac{8}{5} \\ \text{Then} \\ 5x=56 \\ x=\frac{56}{5}=11.2 \end{gathered}[/tex]

Therefore

x=11.2

The area of the image when some part of the picture are chopped off

[tex]10\times8=80in^2[/tex]

The area of the main image will be

[tex]11.2\times8=89.6in^2[/tex]

Then

The percentage of the picture that can be used is

[tex]\frac{80}{89.6}\times100=89.29\text{ \%}[/tex]

Therefore

The percentage of the picture that can be used is 89.29%

Ver imagen BriannC32489
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