A person wants to increase a (5 in. x 7 in.) photo to an (8 in. x 10 in.) but since the aspect ratios are not the same some of the picture will get chopped off.

SOLUTION
Consider the image below
The image should have the leghth x
Hence by comparing the ratio of the side
[tex]\begin{gathered} \frac{x}{7}=\frac{8}{5} \\ \text{Then} \\ 5x=56 \\ x=\frac{56}{5}=11.2 \end{gathered}[/tex]Therefore
x=11.2
The area of the image when some part of the picture are chopped off
[tex]10\times8=80in^2[/tex]The area of the main image will be
[tex]11.2\times8=89.6in^2[/tex]Then
The percentage of the picture that can be used is
[tex]\frac{80}{89.6}\times100=89.29\text{ \%}[/tex]Therefore
The percentage of the picture that can be used is 89.29%