Question

A 50.0-g Super Ball traveling at 28.5 m/s bounces off a brick wall and rebounds at 18.0 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 4.00 m/s,what is the magnitude of the average acceleration of the ball during this time interval?m/s

Answer 1

Given data:

*The given mass of the Superball is m = 5.0 g

*The initial speed of the Superball is u = -28.5 m/s

*The ball rebounds at a final speed is v = +18.0 m/s

*The given time is

$t=4.00ms=4.00\times10^{-3}\text{ s}$

Considering the rebound direction is positive

The formula for the magnitude of the average acceleration of the ball during this time interval is given as

$a_{avg}=\frac{v-u}{t}$

Substitute the known values in the above expression as

$\begin{gathered} a_{avg}=\frac{18.0-(-28.5)}{(4.0\times10^{-3})} \\ =11625m/s^2 \end{gathered}$