Object distance, u = 26.0 cm
Focal length, f = -14.0 cm
Image distance, v = ?
The relationship between object distance, image distance, and focal length is:
[tex]\begin{gathered} \frac{1}{f}=\frac{1}{u}+\frac{1}{v} \\ \\ -\frac{1}{14}=\frac{1}{26}+\frac{1}{v} \\ \\ \frac{1}{v}=-\frac{1}{14}-\frac{1}{26} \\ \\ \frac{1}{v}=-0.10989010989 \\ \\ v=\frac{-1}{0.10989010989} \\ \\ v=-9.1\text{ cm} \\ \end{gathered}[/tex]Magnigication is calculated as:
[tex]\begin{gathered} M=|\frac{v}{u}| \\ \\ M=|\frac{-9.1}{26}| \\ \\ M=0.35 \end{gathered}[/tex]The magnification of the object = 0.35
