Question

See photo. I am particularly confused about how specific latent heat factors into it

Answer 1

Given:

Initial temperature, T1 = 20.0 degrees Celsius

Final temperature, T2 = -1.5 degrees celsius

Energy, Q= 165 kJ

Specific heat capacity of the mixture, c = 3500 J/kg degrees Celsius

Sppecific latent heat, L = 255000 J/kg

Let's find the mass of the mixture.

Apply the formula:

$Q=mc\Delta T+mL$

Where:

m is the mass

Rewrite the formula for m

Thus, we have:

$m=\frac{Q}{c\Delta T+L}$

Now, input values and solve for m:

$\begin{gathered} m=\frac{Q}{c(T_2-T_1)+L} \\ \\ m=\frac{165000}{3500(-1.5-20)+255000} \\ \\ m=\frac{165000}{3500(-21.5)+255000} \end{gathered}$

Solving further:

$\begin{gathered} m=\frac{165000}{-75250+255000} \\ \\ m=\frac{165000}{179750} \\ \\ m=0.92kg \end{gathered}$

Therefore, the mass of the mixture is 0.92 kg