Illuminance is inversely proportional to the square of the distance from the light source.
Then, if we decrease the distance to 1/3, the illuminance will grow up to a factor of 1/(1/3)^2:
[tex]\frac{1}{(\frac{1}{3})^2}=\frac{1}{(\frac{1}{9})}=9[/tex]Therefore, the answer is:
2) The illuminance will be multiplied by 9.