Question

The graphs of two trigonometric functions, f(a) = 4cos(0 - 90°) and g(a) = 2 cos(0 - 90°) + 1, are shown below. The function g(s) is subtractedfrom the function f(x) to get a new function A(x). What is the minimum value of A(z)?-1-5-3-3.2

Answer 1

Answer: -3

First, let us find the value of A(x).

We know that A(x) = f(x) - g(x)

Given that:

$f(x)=4\cos (\theta-90)$$g(x)=2\cos (\theta-90)+1$

We know that

$A(x)=4\cos (\theta-90)-(2\cos (\theta-90)+1)$

Using trigonometric identities, we can rewrite this as

$A(x)=4\sin (\theta)-(2\sin (\theta)+1)_{}$

Subtract, and we will get

$A(x)=2\sin (\theta)-1$

Now, to find it's minimum value, we will plug in 3π/2 from the interval to 2sin(θ)-1, and we will get a value of y = -3.

Therefore, the minimum value of A(x) is -3.