Respuesta :

Given:

[tex]f(x)=x^3-12y^2+x-2y[/tex]

Required:

We need to find the x-intercept.

Explanation:

Substitute f(x)=0 and y =0 in the given equation to find the x-intercept.

[tex]0=x^3-12(0)+x-2(0)[/tex][tex]0=x^3+x[/tex][tex]0=x(x^2+1)[/tex][tex]x=0,x^2+1=0[/tex][tex]x=0,x^2=-1[/tex][tex]x=0,x=\pm\sqrt{-1}[/tex][tex]x=0,x=\pm i[/tex]

The real x-intercepts is x =0.

Final answer:

The real x-intercepts is x =0.

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