How much greater is the mean pages read by class A than the mean number of pages read by B

Determine the mean number of pages read by class A.
[tex]\begin{gathered} \mu_A=\frac{50+49+32+14+33+6+55+39}{8} \\ =\frac{278}{8} \\ =34.75 \end{gathered}[/tex]Determine the mean number of pages read by class B.
[tex]\begin{gathered} \mu_B=\frac{7+43+37+17+19+10+35+14}{8} \\ =\frac{182}{8} \\ =22.75 \end{gathered}[/tex]Determine the difference in mean number of pages read by class A and class B.
[tex]\begin{gathered} \mu_A-\mu_B=34.75-22.75 \\ =12 \end{gathered}[/tex]So answer is 12.