Question

Evaluate the following algebraic expressions for x=6 and y=3x3)y y' - x²

Answer 1

To evaluate the expressions, replace for the given values (x=6; y=3)

$\frac{x^2}{y}=\frac{6^2}{3}=\frac{36}{3}=12$$y^3-x^2=3^3-6^2=27-36=-9$