Given the function:
[tex]B(t)=800(0.65)^{\frac{t}{12}}[/tex]if we look only at the growth factor with its exponent, we have:
[tex](0.65)^{\frac{t}{1}}=(\lbrack0.65\rbrack^{\frac{1}{12}})^t=(0.96)^t[/tex]therefore, an equivalent expression that represent the monthly percent change is:/
[tex]B(t)=800(0.96)^t[/tex]