Question

←++N-5-4-3-2655+पं32(0.0.2)(3, 2.2)X49:2Which linear inequality is represented by the graph?Oy> x-Oy² = x +0y≤ x +Oy

Answer 1

Looking at the graph

The solution is the shaded area below the solid line

so

The inequality is of the form

$y\leq mx+b$

so

Find out the equation of the solid line

we have the points

(0,0.2) and (3,2.2)

Find out the slope

m=(2.2-0.2)/(3-0)

m=2/3

the equation of the solid line is

$y=\frac{2}{3}x+0.2$

therefore

The inequality is equal to

$y\leq\frac{2}{3}x+0.2$

Remember that

0.2=1/5

so

$y\leq\frac{2}{3}x+\frac{1}{5}$