Respuesta :

Given:

[tex](2,2)\text{ and (4,5) are the points on the line}[/tex]

Equation of the line is

c)

[tex]\begin{gathered} \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \frac{y-2}{5-2}=\frac{x-2}{4-2} \\ y-2=\frac{3}{2}(x-2) \\ y-2=1.5(x-2) \end{gathered}[/tex]

D)

[tex]\begin{gathered} y-2=1.5x-3 \\ y=1.5x-1 \end{gathered}[/tex]

A)

[tex]\begin{gathered} y-5=1.5(x-4) \\ y-5=1.5x-6 \\ y=1.5x-1 \end{gathered}[/tex]

Option A,C and D are the equations for the line.

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