we have the equation
[tex]D=10\log (10^{(12)}\cdot I)[/tex]Part a) we have
I=6.3x10^6
substitute in the given formula and solve for D
[tex]\begin{gathered} D=10\log (10^{(12)}\cdot6.3\cdot10^6) \\ D=10\log (6.3\cdot10^{(18)}) \\ D=188 \end{gathered}[/tex]we have that
188 is greater than 160
therefore
the sound of blue whale can rupture the human eardrum
Part b
For I=3.2x10^-6
substitute in the given formula
[tex]\begin{gathered} D=10\log (10^{(12)}\cdot3.2\cdot10^{(-6)}) \\ D=10\log (3.2\cdot10^{(6)}) \\ D=65.05 \end{gathered}[/tex]answer part b is 65 decibels