Question

Writing Linear equations given two points(3, 3) and (1, -3)

Answer 1

The slope of the line that passes through points (x1 ,y1) and (x2, y2) is computed as follows:

$m=\frac{y_2-y_1}{x_2-x_1}$

Replacing with points (3, 3) and (1, -3) :

$m=\frac{-3-3}{1-3}=\frac{-6}{-2}=3$

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept. Replacing with point (3, 3) and m = 3:

3 = 3(3) + b

3 = 9 + b

3 - 9 = b

-6 = b

Then, the equation is:

y = 3x - 6