The foci of the hyperbola lie on the circle. Write an equation of the circle. Show all work.The equation of the hyperbola: \small \frac{x^2}{4}-\frac{y^2}{5}=1

Given the equation of the hyperbola:
[tex]\frac{x^2}{4}-\frac{y^2}{5}=1[/tex]The general equation of the hyperbola:
[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]Comparing the given equation with general form:
[tex]\begin{gathered} a^2=4,b^2=5 \\ c^2=a^2+b^2=4+5=9 \\ c=\pm\sqrt[]{9}=\pm3 \end{gathered}[/tex]So, the coordinates of the foci are:
[tex](-3,0),(3,0)[/tex]Now, we will find the equation of the circle that has a diameter with the endpoints (-3, 0) and (3,0)
The center of the circle = (0,0)
and the radius of the circle = r = 3
the general equation of the circle with the center (0,0) is as follows:
[tex]x^2+y^2=r^2[/tex]So, the answer will be the equation of the circle will be:
[tex]x^2+y^2=9[/tex]