Question

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Answer 1

Question:

Solution:

Consider the following system of equations:

$y=x^2-3x-8$$y\text{ = 3x+8}$

then, the above system of the equation has a solution if both equations are equal, that is:

$x^2-3x-8\text{ = 3x+8}$

this is equivalent to say:

$x^2-3x\text{ + 3x -8 +8 = 0}$

this is equivalent to:

$x^2\text{ = 0}$

then

$x\text{ = 0}$

now, replacing the above value in the second equation, we obtain:

$y\text{ = 3(0)+8}=\text{ 0+8 = 8}$

thus:

$y\text{ = 8}$

then, we can conclude that the correct answer is:

$x\text{ = 0 }$

and

$y\text{ = 8}$

that is 0 and 8.