How do I find the measure of angle X to the nearest 10th?

Solution:
Given the right triangle MXN as shown below:
To evaluate the measure of angle X to the nearest tenth,
step 1: Identify the sides of the triangle.
In the triangle MXN, using the angle X as the angle of focus,
[tex]\begin{gathered} XM\Rightarrow\text{adjacent} \\ MN\Rightarrow\text{opposite} \\ XN\Rightarrow\text{hypotenuse} \end{gathered}[/tex]step 2: Evaluate the measure of angle X using trigonometric ratios.
From trigonometric ratios,
[tex]\cos \theta=\frac{\text{adjacent}}{\text{hypotenuse}}[/tex]where
[tex]\theta=X[/tex]thus,
[tex]\begin{gathered} \cos X=\frac{\text{adjacent}}{\text{hypotenuse}} \\ =\frac{XM}{XN} \\ \text{where } \\ XM=15,\text{ XN=}20 \\ \text{thus,} \\ \cos X=\frac{15}{20} \\ =0.75 \\ \Rightarrow X=\cos ^{-1}(0.75)^{} \\ =41.40962211 \\ \therefore X\approx41.4\degree\text{ (nearest tenth)} \end{gathered}[/tex]Hence, the measure of the angle X to the nearest tenth is 41.4 degrees.