Respuesta :

First let's create the sample space of the experiment

let S denotes the sport car , T denote the pick up truck and R denotes the grandma ride.

Then the possible combinations will be

[tex]\begin{gathered} (S,New),(S,Good),(S,Poor),(S,Fair), \\ (T,New),(T,Good),(T,Poor),(T,Fair), \\ (R,New),(R,Good),(R,Poor),(R,Fair), \end{gathered}[/tex]

Now let E deontes the event of getting grandma ride and F denotes the event of getting new vehicle

Then

[tex]n(E\cap F)=1[/tex]

So

[tex]P(E\cap F)=\frac{1}{12}[/tex]

So the probabilty of getting a grandma ride and a vehicle in new condition is 1/12

Now let A denote the event of getting a sports car and B denote the event of getting a vehicle in fair condition so

[tex]n(A\cup B)=6[/tex]

So

[tex]P(A\cup B)=\frac{6}{12}[/tex]

So the probabilty of getting a sports car or a vehicle in fair condition is 6/12

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EDU ACCESS
Universidad de Mexico