Given:
Hel;icopter elevation from ground AB=450 feet
Depression to the landing is 16 degree
[tex]\angle ACB=\angle DAC=16^{\circ}[/tex][tex]\begin{gathered} \tan \theta=\frac{AB}{BC} \\ \tan 16^{\circ}=\frac{450}{BC} \\ BC=\frac{450}{0.2867} \\ BC=1569.58\text{ feet} \end{gathered}[/tex]The distance between a point on the ground directly below the helicopter and the landing pad is 1569.58 feet