Respuesta :

Given: Two triangles with their areas and sides and the proportion

Required: The value of x.

Explanation:

Put the values of areas and sides in the given proprtion:

Area of left triangle is given as 34 inches square

Area of right triangle is given as 96 inches square

Side of left triangle is 10 in

Side of right triangle is x

Putting these values

[tex]\frac{34}{96}=(\frac{10}{x})^2[/tex]

Solve for x

[tex]\begin{gathered} \frac{34}{96}=\frac{100}{x^2} \\ x^2=\frac{9600}{34} \end{gathered}[/tex]

So

[tex]\begin{gathered} x^2=282.35 \\ x=16.8 \end{gathered}[/tex]

So the value of x is 16.8 inches.

Final Answer x is 16.8 inches.

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